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40 lines (38 loc) · 1.01 KB
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/*You are required to complete this method*/
int maxHist(int R[],int n,int m){
stack<int> result;
int top_val,max_area=0,area=0;
int i=0;
while(i<m){
if(result.empty() || R[result.top()]<=R[i])
result.push(i++);
else{
top_val=R[result.top()];
result.pop();
area=top_val*i;
if(!result.empty())
area=top_val*(i-result.top()-1);
max_area=max(area,max_area);
}
}
while(!result.empty()) {
top_val = R[result.top()];
result.pop();
area=top_val*i;
if(!result.empty())
area=top_val*(i-result.top()-1);
max_area=max(area,max_area);
}
return max_area;
}
int maxArea(int M[MAX][MAX], int n, int m) {
int result=maxHist(M[0],n,m);
for(int i=1;i<n;i++){
for(int j=0;j<m;j++){
if(M[i][j])
M[i][j]+=M[i-1][j];
}
result=max(result,maxHist(M[i],n,m));
}
return result;
}