Source lookup fails for paths with “.zip_\” segment #1964

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Environment data

• debugpy version: 1.8.15
• OS and version: XXX: Microsoft Windows 11 Enterprise , 10.0.22631 N/A Build 22631
• Python version : Python 3.8.9
• Using VS Code or Visual Studio: VS Code

Actual behavior

When attaching from VS Code (debugger in listen mode) to a target process that calls debugpy.connect(...), if the script’s path contains a directory segment like ...\archive.zip_\files... (this is a normal folder, not an archive), VS Code shows:
Unable to retrieve source for C:\repro\archive.zip_\files\app\script.py
Note the path is displayed as zip_\files, whereas the actual on-disk path is zip_\files. Because of this mismatch, the source cannot be opened, breakpoints remain unresolved, and stepping falls back to a top-level exec frame.

Renaming the folder so it does not contain .zip_ makes the problem disappear.

Expected behavior

The debugger should treat the file system path literally and open the source without rewriting segments around .zip. Breakpoints should bind and stepping should work normally for any valid Windows path.

Steps to reproduce:

1. Create the following directory structure:
   C:\repro\archive.zip_\files\app\

2. Create C:\repro\archive.zip_\files\app\script.py with:
   import debugpy
   debugpy.connect(("127.0.0.1", 9092))
   debugpy.breakpoint()
   print(file)

In VS Code, open C:\repro\archive.zip_\files\app\ as the workspace and add .vscode/launch.json:
{
"version": "0.2.0",
"configurations": [
{
"name": "Listen 9092",
"type": "python",
"request": "attach",
"listen": { "host": "127.0.0.1", "port": 9092 },
"pathMappings": [
{
"remoteRoot": "C:\repro\archive.zip_\files\app",
"localRoot": "C:\repro\archive.zip_\files\app"
}
],
"justMyCode": true
}
]
}

3. Start the Listen 9092 configuration in VS Code.
4. In a separate console, run: python C:\repro\archive.zip_\files\app\script.py
5. BOOM