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Add solution for Challenge 19 by azs0309 #919
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WalkthroughAdds a new Go file containing four exported slice utility functions (FindMax, RemoveDuplicates, ReverseSlice, FilterEven) and a main function demonstrating their usage with sample data. Functions handle empty inputs gracefully. Changes
Estimated code review effort🎯 2 (Simple) | ⏱️ ~10 minutes
Possibly related PRs
Pre-merge checks✅ Passed checks (3 passed)
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Actionable comments posted: 1
🧹 Nitpick comments (1)
challenge-19/submissions/azs0309/solution-template.go (1)
44-65: Consider using a map for better performance.The current implementation uses nested loops resulting in O(n²) time complexity. For larger slices, this could impact performance. A map-based approach would reduce this to O(n).
🔎 Proposed refactor using a map
func RemoveDuplicates(numbers []int) []int { if len(numbers) == 0{ return []int{} } - result := make([]int,0,len(numbers)) - - result = append(result, numbers[0]) + seen := make(map[int]bool) + result := make([]int, 0, len(numbers)) + for _, number := range numbers { - found := false - for _, inresult := range result { - if number == inresult { - found = true - } - } - if !found { + if !seen[number] { + seen[number] = true result = append(result, number) } } return result }
📜 Review details
Configuration used: Organization UI
Review profile: CHILL
Plan: Pro
📒 Files selected for processing (1)
challenge-19/submissions/azs0309/solution-template.go(1 hunks)
🔇 Additional comments (4)
challenge-19/submissions/azs0309/solution-template.go (4)
7-26: LGTM! Clear demonstration code.The main function effectively demonstrates all utility functions with appropriate test data and output.
28-42: LGTM! Efficient maximum-finding implementation.The function correctly finds the maximum value with O(n) time complexity and handles empty slices as documented.
75-79: LGTM! Correct reverse implementation.The reverse logic correctly iterates backwards and builds the reversed slice efficiently.
82-95: LGTM! Correct even number filtering.The function correctly filters even numbers using the modulo operator and handles empty input appropriately.
| // if len(slice) == 1{ | ||
| // return slice | ||
| // } |
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🛠️ Refactor suggestion | 🟠 Major
Remove commented-out code.
The commented lines are unnecessary dead code and should be removed to keep the codebase clean.
🔎 Proposed fix
if len(slice) == 0{
return []int{}
}
-// if len(slice) == 1{
-// return slice
-// }
reversed := make([]int,0,len(slice))📝 Committable suggestion
‼️ IMPORTANT
Carefully review the code before committing. Ensure that it accurately replaces the highlighted code, contains no missing lines, and has no issues with indentation. Thoroughly test & benchmark the code to ensure it meets the requirements.
| // if len(slice) == 1{ | |
| // return slice | |
| // } | |
| if len(slice) == 0{ | |
| return []int{} | |
| } | |
| reversed := make([]int,0,len(slice)) |
🤖 Prompt for AI Agents
In challenge-19/submissions/azs0309/solution-template.go around lines 72 to 74,
there are three commented-out lines (an if len(slice) == 1 check and return)
that are dead code; remove these commented lines entirely to clean up the file
and keep the codebase tidy, leaving no leftover commented logic.
Challenge 19 Solution
Submitted by: @azs0309
Challenge: Challenge 19
Description
This PR contains my solution for Challenge 19.
Changes
challenge-19/submissions/azs0309/solution-template.goTesting
Thank you for reviewing my submission! 🚀